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习题练习:SL/HL Topic C1.1 Enzymes and metabolism

 作者: admin   总分: 16分  得分: _____________

答题人: 游客未登录  开始时间: 25年01月31日 10:44  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/4) 切至整卷模式 搜藏此题  
第 1 题组 (共 4 题 4 分)
  1. How is reliability es2f e:of8b9 2y dnjt)vlevx9 2-pkvqw/ tablished in an enzyme experiment?

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2#
 
单选题 ( 1.0 分) (组内2/4) 切至整卷模式 搜藏此题  
  2. What can cause an enzyme tog) b ,hry7. eblp;g(ex i;j0gt be denatured?

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3#
 
单选题 ( 1.0 分) (组内3/4) 切至整卷模式 搜藏此题  
  3. Which of the following correctly describe aspects of a mex 9d8: -p/5)w/lysuy8+wbzxtcsi ev r tabolic pathway?
I. It is regulated by one enzyme.
II. It is a series of reactions to produce an end product.
III. It is a system producing energy.
IV. It can be anabolic or catabolic in nature.

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4#
 
单选题 ( 1.0 分) (组内4/4) 切至整卷模式 搜藏此题  
  4. The binding of the substrate to the active site of an enzyme causes which ar ( (pskvdxt e051+jlof the following chv pa1t 50 (jd+rxkes(langes?
I. A change in the shape of the active site.
II. A change in the shape of the substrate.
III. A lowering of the activation energy of the reaction.
IV. The denaturation of the enzyme.

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5#
 
问答题 ( 1.0 分) (组内1/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第1/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
I. Explain why glucoses:m mcq33vbk, iun z2b8)k6hpbe61 fo is formed in the reaction mixture.
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6#
 
问答题 ( 1.0 分) (组内2/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第2/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
II. List two variables thacga ,x zbkjim,a; j. pg017v qu2z 7/g2h(yjvkt should be controlled in this experiment, other than th2,zv7uh .jpg,1 ja2gqzgk/cv0m ji(;7bxak y ose given.
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7#
 
问答题 ( 1.0 分) (组内3/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第3/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
III. Does the data collected indicate that the rate of the reacgy6 t8 +j-wkmtekq n1-tion is constant i-tq18kjk+-m6w e gny tn the first 3 minutes?
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8#
 
问答题 ( 1.0 分) (组内4/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第4/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
IV. Calculate the rate of ;ktf 9mo9q4 sa)whe, hreaction in the first 5 minutes
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9#
 
问答题 ( 1.0 分) (组内5/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第5/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
V. Describe the changes nu,hmh ix1-xh-xd,b.in the rate of reaction from the $4^{th}$ to the $8^{th}$ minute.
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10#
 
问答题 ( 1.0 分) (组内6/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第6/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VI. Why was it not necessa6 +nv16(o/g q stzucuory to collect data after the $8^{th}$ minute?
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11#
 
问答题 ( 1.0 分) (组内7/7) 切至整卷模式 搜藏此题  
第 2 题组 (共 7 题 7 分) 当前第7/7题
题组内容描述:
5. Invertase is a hydrolysing enzyme which hydrolyses the disaccharide sucrose into the monosaccharides glucose and fructose. In an investigation,$10 cm^3$of 1% invertase was added to$10 cm^3$of 1% sucrose in a$50cm^3$ beaker. Every minute, the concentration of glucose was measured using a glucose meter which directly reads the concentration of glucose in a solution in $mmol/dm^3$.The raw data is given In the table below:
VII. Predict, with a reason, the fructose concentration ik 5i)qt-9v-y2)oc 0xx lh)clq zl yi.qn the reaction mixture vhq --.z)9 iyciq )x50 k2xll tco)yqlat the $6^{th}$ minute.
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12#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 3 题组 (共 1 题 1 分)
6. Enzymes are specific to a partic20pnp5dvml5 ri:m cm.ular reaction. Explain why enzyme specificity is important in the control of r50cm:dv 52 pin lmpm.metabolic pathways.
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13#
 
问答题 ( 1.0 分) (组内1/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第1/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
I. Penicillin does not 9ca-+ry -dkjj(i9jq h affect human enzymes.
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14#
 
问答题 ( 1.0 分) (组内2/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第2/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
II. Penicillin is a permanent competitive inhibitor of transpeptidasz xj3-x :dee4b/0 q3iabwr lk+e.
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15#
 
问答题 ( 1.0 分) (组内3/3) 切至整卷模式 搜藏此题  
第 4 题组 (共 3 题 3 分) 当前第3/3题
题组内容描述:
7. Penicillin is an antibiotic which is a competitive inhibitor of a transpeptidase enzyme in bacteria. This enzyme is involved in creating peptide cross links between the polysaccharide polymers found in peptidoglycan call walls in prokaryote cells.Use your knowledge of enzyme function to explain the following statements:
III. Suggest how penicillin2*)ca9( m b9jny- h3b wwzd5sg08 vxztdqhk7g resistance has developed in some bacteria.
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16#
 
问答题 ( 1.0 分) (组内1/1) 切至整卷模式 搜藏此题  
第 5 题组 (共 1 题 1 分)
8. ATP is an allosteric in)x+t5gqvk81f td (mtshibitor of phosphofructokinase and pyruvate kinase, two enzymes involved in glycolysis. Discuss the importance of feedback inhibition of metabolic pathways in biological systems 5xkt ) vtqd( gstm18+fusing this as an example.
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