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习题练习：HL Topic A3.1 Diversity of organisms
本习题练习试卷来源于无忧得胜-网上国际课程 (https://5edu.win)， 为试卷打印版，您也可以在网站平台(https://5edu.win/)直接 访问本试卷的在线电子版并查看正确答案与解析，搜藏保存任意题目到收藏集。 访问方法: 平台首页左上角"通过试卷号快速访问"输入试卷号 561，并点击直达试卷；或浏览器地址栏内直接输入本试卷链接 https://5edu.win/test561.html  教师使用本平台可以抽题组卷或一键复制他人试卷，布置为在线考试或在线作业，全自动判分成绩一键排序导出，省时省力。
 作者: admin  发布日期: 2025-01-24 21:47    总分: 13分  得分: _____________

答题人: 游客未登录  开始时间: 25年01月24日 11:52  切换到: 整卷模式

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1#
 
单选题 ( 1.0 分) (组内1/8) 切至整卷模式 搜藏此题  
第 1 题组 (共 8 题 8 分)
  1. Which of the follow;m4dbs muxn rys 4f+a na cd2b8k8:w;3q,y s6bing could be a difference between the members of two distinct species but could not be a diffebayn 8 n2wubdsab4f;+:myq3; 4 mx 6c sk8,srdrence between members of the same species?

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2#
 
单选题 ( 1.0 分) (组内2/8) 切至整卷模式 搜藏此题  
  2. Which of the following is the correct binomimj, nazd*we 5;al name for the Great white egret shown in the imj*z,e5 ;n wdmaage?


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3#
 
单选题 ( 1.0 分) (组内3/8) 切至整卷模式 搜藏此题  
  3. If two populations are separa-byxu4 r, nieqr20 bb7ted by a geographical barrier such as a mountainenru0 4x2bb -i7yb, qr range and cannot interbreed, which reason on its own would be enough to classify them as two separate species?

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4#
 
单选题 ( 1.0 分) (组内4/8) 切至整卷模式 搜藏此题  
  4. In relation to two distinct isolated poocd;1tjk gk,g-1 3zudpulations, which technique might be used tok-ukdd;g1 t ,g z13jco decide if they ae closely related in evolutionary terms?

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5#
 
问答题 ( 1.0 分) (组内5/8) 切至整卷模式 搜藏此题  
6. There is evidence 4ic yp9cf5m8r8as+a ythat chromosome 2 in humans arose from the fusion of chromosomes 12 and 13 in a common human ancestor. The image below shows the bandi4 +89 afsary8yi cm5cpng patterns of chromosomes found
in modern humans and chimpanzees.

Outline the evidence that could support this chromosome fusion hypothesis.
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6#
 
问答题 ( 1.0 分) (组内6/8) 切至整卷模式 搜藏此题  
7. Risso’s dolphin, (Grampus griseus) h x:i67kmnudz4as a diploid chromosome number of 40, Common bottle-nose dolphins (Tursiops truncates) have a diploid number k 7xnudi6:z4mof 44. There have been reliable sightings of hybrid Risso’s and Bottle nose dolphins in the wild.
Suggest why such a hybridisation is very uncommon but is possible.
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7#
 
问答题 ( 1.0 分) (组内7/8) 切至整卷模式 搜藏此题  
8. Explain why the biological species concept cannot bevt j(.xau q6:j/*a eog precisely applied to Prokaryotes6( uxv/ja qj og*et.a:.
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8#
 
问答题 ( 1.0 分) (组内8/8) 切至整卷模式 搜藏此题  
9. Outline a method using DNA analysis that can be used to de3 5cqdbjvh1 pjk60 hx7termine the biodiversity of 6j1dhxbqc53v h pk0 j7an ecosystem.
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9#
 
问答题 ( 1.0 分) (组内1/5) 切至整卷模式 搜藏此题  
第 2 题组 (共 5 题 5 分) 当前第1/5题 
题组内容描述:
5. The table shows the diploid chromosome number of a certain mammals, their approximate body mass in Kg and their genome size in Gbp.
(a) Outline the meanij42ebd6/ r.ccx-l hk e02fcwgng of the term genome size
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10#
 
问答题 ( 1.0 分) (组内2/5) 切至整卷模式 搜藏此题  
第 2 题组 (共 5 题 5 分) 当前第2/5题 
题组内容描述:
5. The table shows the diploid chromosome number of a certain mammals, their approximate body mass in Kg and their genome size in Gbp.
(b) Explain why the diploid number of chromosomes is an even ;(/n o2ko yrev8ea.drnumber for all speci o(y/na2d8o.k rver;ees.
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11#
 
问答题 ( 1.0 分) (组内3/5) 切至整卷模式 搜藏此题  
第 2 题组 (共 5 题 5 分) 当前第3/5题 
题组内容描述:
5. The table shows the diploid chromosome number of a certain mammals, their approximate body mass in Kg and their genome size in Gbp.
(c) Suggest two reasons why the genome size has little vari lchp,2y v4r*xation between species and thrlyvh,4cp 2 x*e masses of mammals has wide variation.
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12#
 
问答题 ( 1.0 分) (组内4/5) 切至整卷模式 搜藏此题  
第 2 题组 (共 5 题 5 分) 当前第4/5题 
题组内容描述:
5. The table shows the diploid chromosome number of a certain mammals, their approximate body mass in Kg and their genome size in Gbp.
(d) Discuss whether a larger genom:qd-5n1cqi gje size is caused by a larger number of chromosomes d-1ncig5q:jq in a diploid cell.
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13#
 
问答题 ( 1.0 分) (组内5/5) 切至整卷模式 搜藏此题  
第 2 题组 (共 5 题 5 分) 当前第5/5题 
题组内容描述:
5. The table shows the diploid chromosome number of a certain mammals, their approximate body mass in Kg and their genome size in Gbp.
(e) Explain why two genomes of individuals a+ k.zj r7ia;tfrom a single species would show less difference than two genomes of individuals from r;.zka+jiat7 two different species.
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