SL/HL Topic D1.2 Protein synthesis - 无忧得胜-网上国际课程 (5edu.win)

1#

第 1 题组 (共 5 题 5 分)

1. Which enzyme is responsi:bww rdq b **coq.uj05ble for the breaking of the hydrogen bonds in DNA to allow transc:bw5*ojdq .b0qwcru *ription to occur?

A. Helicase.

B. Gyrase.

C. RNA polymerase

D. Translatase.

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2#

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2. How can different tissues in the same organism produceiyx5 l2 gr6+eg different proteins?

A. The genetic code varies between cells.

B. Expression of different genes can be activated in different tissues.

C. There are different genes in the tissues of the same organism.

D. Tissues only contain the genes they need to manufacture protein.

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3#

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3. How do cells control the proteins afxv1p n l,bo*:p4a+pmanufactured by the cell?

A. By controlling translation.

B. By controlling transcription.

C. By using different ribosomes.

D. By controlling replication.

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4#

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4. Which of the follo0ftvk las3c+9*a h8bqyqz fwxl6s 469 wing is correct in regard to the genetic code?

A. The genetic code is different in different species.

B. The genetic code varies between individuals.

C. The genetic code allows translation to form a polypeptide.

D. The genetic code allows transcription to form a polypeptide.

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5#

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5. The human DNA base sequence for the insulin gene can be insew q t5moz 37:qd1gnvpx6om/7frted into bacteria. The bacteria will then manufacture the protein, insulin. Why camogx q3f7 o6dn/ 1ztp7qmv: 5wn bacteria utilise a human gene to manufacture insulin?

A. The genetic code is universal.

B. Bacteria and humans have the same genes.

C. Bacteria naturally manufacture insulin.

D. The genetic code is degenerate.

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6#

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第 2 题组 (共 4 题 4 分) 当前第1/4题

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6. The table shows the genetic code. It gives the base sequence and the amino acid (3-letter code) into which it is translated. Use the information in the image to answer the questions.

I. Which molecule’s base sequence is shown injipo )a dxu5v:,lh9 n*zy+- yl+:she t the table?

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7#

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第 2 题组 (共 4 题 4 分) 当前第2/4题

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6. The table shows the genetic code. It gives the base sequence and the amino acid (3-letter code) into which it is translated. Use the information in the image to answer the questions.

II. Explain why a point mutation of CAU to CAG,:fke7p 0d4bcee k 2avqi u38e would cause a change in the polypeptide sequence of a protein but a point mutation of CAU to CAC would not cause any change in the polypeptide s,3a:fe7beqcu4 v8dik 0epk2eequence.

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8#

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6. The table shows the genetic code. It gives the base sequence and the amino acid (3-letter code) into which it is translated. Use the information in the image to answer the questions.

III. Which bases would be present r+.l(comcv r 3on the anticodon of the transfer RNA molecule which carries the ami+3 l.vrc(cr omno acid tryptophan (Trp)?

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9#

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6. The table shows the genetic code. It gives the base sequence and the amino acid (3-letter code) into which it is translated. Use the information in the image to answer the questions.

IV. Deduce the amino acid sequence that would cs;7/p) 7n f sz;kgtzcbe translated from an mRNA molecule with a base sequence of AUGAGGACUGCUUGA. Use the 3-letter codes in the ts;c7tfpk/z;c7n g)s z able

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10#

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第 3 题组 (共 4 题 4 分)

7. Discuss why complimentary base pas/c,avxl x)u,jph e 8-iring is essential in converting a base sequence in DNA to a polypeptide sequence in a povxcap-x sj/, u eh8l),lypeptide chain.

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11#

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8. A ribosome produces a polypeptide sequence from a sequence of bases in thv jthfyw63d ibk)c .1ps h2r4:hlp--te mRNA molecule. Explain how a polypeptide chain elongates as the ribosome.3i:1-dv46- ykbcphjh ) swpttflrh 2 moves along an mRNA molecule.

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12#

问答题 ( 1.0 分) (组内3/4) 切至整卷模式搜藏此题

9. Translation and transcription both occur unidirectionally in a 5’ 3’ directivf)4dg + n-cp .aykso0on. Explain why this isa4cgdf)kvp y.o+n- s0 essential in the case of translation.

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13#

问答题 ( 1.0 分) (组内4/4) 切至整卷模式搜藏此题

10. Describe 3 ways in which mature mRNAko5w3m-fbfu 7wv4xg5 is different to the mRNA produced by translatu4- fb5vx3 7fowmk5g wion.

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